20x^2+4y^2=5

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Solution for 20x^2+4y^2=5 equation: 


Simplifying
20x2 + 4y2 = 5

Solving
20x2 + 4y2 = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y2' to each side of the equation.
20x2 + 4y2 + -4y2 = 5 + -4y2

Combine like terms: 4y2 + -4y2 = 0
20x2 + 0 = 5 + -4y2
20x2 = 5 + -4y2

Divide each side by '20'.
x2 = 0.25 + -0.2y2

Simplifying
x2 = 0.25 + -0.2y2

Reorder the terms:
-0.25 + x2 + 0.2y2 = 0.25 + -0.2y2 + -0.25 + 0.2y2

Reorder the terms:
-0.25 + x2 + 0.2y2 = 0.25 + -0.25 + -0.2y2 + 0.2y2

Combine like terms: 0.25 + -0.25 = 0.00
-0.25 + x2 + 0.2y2 = 0.00 + -0.2y2 + 0.2y2
-0.25 + x2 + 0.2y2 = -0.2y2 + 0.2y2

Combine like terms: -0.2y2 + 0.2y2 = 0.0
-0.25 + x2 + 0.2y2 = 0.0

The solution to this equation could not be determined.

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